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  1. definition - What is Convolution? - Mathematics Stack Exchange

    2015年9月6日 · The definition of convolution is known as the integral of the product of two functions $$(f*g)(t)\int_{-\infty}^{\infty} f(t -\tau)g(\tau)\,\mathrm d\tau$$ But what does the …

  2. What is convolution, how does it relate to inner product?

    2022年10月25日 · Convolution is a way of collecting like terms in a discrete or continuous sum. For example, \begin{align} ...

  3. Definition of convolution? - Mathematics Stack Exchange

    Based on your connection, it seems to me that convolution therefore defines a different "natural multiplication" between functions if we consider functions $\mathbb{R} \to \mathbb{R}$ as …

  4. real analysis - Convolution of two gaussian functions

    2016年4月16日 · You should end up with a new gaussian : take the Fourier tranform of the convolution to get the product of two new gaussians (as the Fourier transform of a gaussian is …

  5. Intuition behind convolution - Mathematics Stack Exchange

    Intuition for Convolution. A convolution is an amount of overlap of one function f as it is shifted over another function g at a given time offset. Let’s say we are transforming a certain function …

  6. analysis - History of convolution - Mathematics Stack Exchange

    2015年7月4日 · The convolution has a nice property, when Fourier transformed: $$ \mathcal{F}(f*g) = c \, \mathcal{F}(f) \mathcal{F}(g) $$ for some constant specific to the …

  7. real analysis - On the closedness of $L^2$ under convolution ...

    Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their …

  8. Convolution $f*g$ is continuous - Mathematics Stack Exchange

    convolution. Related. 14. Convolution is uniformly continuous and bounded. 12. convolution of ...

  9. Derivative of convolution - Mathematics Stack Exchange

    Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their …

  10. calculus - Proof of associativity of convolution - Mathematics Stack ...

    I intend to prove the associativity of convolution but failed after several trials, i.e. $(f \ast g) \ast h = f \ast (g \ast h)$ where $(f \ast g)(t) = \int^{t}_{0}f(s)g(t-s)ds $ There are a number of proves …