Oct 10, 2015 · Remember that #tan=sin/cos# therefore, you will have a vertical asymptope whenever cos=0. Cos=0 every odd multiple of #pi/2#. If you plug y=tan(x) into a graphing calculator you will see that the ends of each section continue on infinitely along the y-axis.

Sep 21, 2015 · graph{tan x [-10, 10, -5, 5]}. See explanation. graph{tan x [-10, 10, -5, 5]} The number of lines you have to draw depends on the domain provided. If the domain is not specifically provided, you will have to draw them all (that's what the function does). If you're doing it by hand, I would first trace some vertical construction lines (asymptotic lines) at pi/2, -pi/2, …

Apr 17, 2015 · The period of tan x is pi. You can see it on the graph: graph{tanx [-10, 10, -5, 5]} Example: tan pi/4 and tan (pi/4 + pi) have the same value (1).

Apr 10, 2017 · tanx = sinx/cosx domain is all the values that x can take such that y always exists and is finite for that value of x. thus x can take all such values where cosx is not zero because if cosx will be zero tanx will become infinity and hence not defined . thus domain is : all real numbers except the numbers at which cosx is zero i.e. npi/2 where n= 1,3,5,..... range of tanx …

Jun 11, 2018 · Below y=tan(x-pi/2) is basically y=tanx shifted to the right by pi/2 That means that the entire graph including the asmpytotes move to the right by pi/2 units. graph{tanx [-10, 10, -5, 5]} Above is y=tanx graph{tan(x-pi/2) [-10, 10, -5, 5]} Above is y=tan(x-pi/2) If you focus on (0,0) in the first graph, you will notice that in y=tan(x-pi/2), it has shifted to the right by pi/2 units or ...

Aug 27, 2014 · I assume that you are asking about the tangent function, so tan theta. The vertical asymptotes occur at the NPV's: theta=pi/2+n pi, n in ZZ. Recall that tan has an identity: tan theta=y/x=(sin theta)/(cos theta). This means that we will have NPV's when cos theta=0, that is, the denominator equals 0. cos theta=0 when theta=pi/2 and theta=(3pi)/2 for the Principal …

Aug 4, 2018 · Graph the given trigonometric function: Note: Constraint #-2 pi < x < 2pi # Parent graph of #y=f(x)=tan(x)# is also available in color #color(red)("RED")# for comparison. Graph of the given function #y=f(x)=[tan(x/2)]# is in #color(blue)("BLUE"# x-intercepts: They happen within the periods of #2pi# i.e., #(-4pi, -2pi,0, 2pi, 4pi)# etc

Nov 19, 2017 · See below. The graph of y=tan3x is the graph of y=tanx with a horizontal compression by a factor of 1/3 The period of tanx is pi, so the period of tan3x is: 1/3*pi=pi/3 Graphs of y=tan3x and y=tanx

Oct 28, 2015 · When a coefficient is present in the function like in this case is 2, the transformation rule states that you should multiply the result of tanx by 2. In the case of tanx When you did tan45, the outcome was 1. Now as the function is 2tanx, the out come is 1*2 i.e 2. SO the graph is, you multiply the values of y of tan x with 2 and it becomes ; graph{2tanx [ …

Dec 18, 2017 · See below. If we look at a trigonometrical function written in the form: y=atan(bx+c)+d We know that: Amplitude = a Period = (pi)/b ( This is the normal period of the function divided by b ) Phase shift = -c/b Vertical shift = d From example: y=tan(x+60) Amplitude ( see below) period = pi/c in this case we are using degrees so: period=180/1=180^@ Phase …