What is the derivative of arctan sqrt x? - Socratic
2015年8月29日 · What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions
What's the derivative of #arctan(2x) - Socratic
2016年2月18日 · What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions
What is the derivative of #y=arctan(x)#? - Socratic
2014年8月30日 · The derivative of #y=arctan x# is #y'=1/{1+x^2}#. We can derive this by using implicit differentiation . Since inverse tangent is hard to deal with, we rewrite it as
How do you find the derivative of #arctan(e^x)#? - Socratic
2016年12月22日 · d/dx arctan(e^x)= (e^x)/(e^(2x)+1) When tackling the derivative of inverse trig functions. I prefer to rearrange and use Implicit differentiation as I always get the inverse …
What is the derivative of #y=arctan(4x)#? - Socratic
2014年7月31日 · Answer 4/(16x^2 + 1) Explanation First recall that d/dx[arctan x] = 1/(x^2 + 1). Via the chain rule: 1.) d/dx[arctan 4x] = 4/((4x)^2 + 1) 2.) d/dx[arctan 4x] = 4/(16x^2 + 1) If it …
What is the derivative of #arctan(2x)#? - Socratic
2015年6月6日 · The general rule for derivating this type of function is y=arctan(u) y'=(u')/(1+u^2) Thus, considering that here u=2x y'=2/(1+(2x)^2)=2/(1+4x^2) Done! :)
What is the derivative of #y=arctan(cos(x))#? - Socratic
2014年9月5日 · This is a case of knowing the how the derivative of inverse tangent works, and then following the chain rule. If we were looking at y=arctan(x), there's a way to determine the …
Differentiating Inverse Trigonometric Functions - Socratic
The trick for this derivative is to use an identity that allows you to substitute #x# back in for #y# because you don't want leave the derivative as an implicit function; substituting #x# back in will …
What is the derivative of #arctan(x)^(1/2)#? - Socratic
dy/dx=1/(2(x^2+1)sqrt(arctanx) ) I usually make no attempt to remember the derivatives of inverse trig function and would have to look up the result.
How do you differentiate #sin(arctan x)#? - Socratic
2016年9月23日 · Note that this matches the other answer, as using the triangle, we can also see that #cos(arctan(x)) = 1/sqrt(x^2+1)#