What is the full taxonomy classification of humans? | Socratic
2018年3月3日 · Domain: Eukarya Kingdom: Animalia Phylum: Chordata Class: Mamallia Order: Primate Family: Hominidae Genus: Homo Species: Sapiens Hope this helps. Eukarya means having ...
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft ...
2017年12月22日 · 20/3 (ft)/s in this diagram, x is the distance from the man to the pole, and y is the distance from the tip of the man's shadow to the pole. i assume the man and pole are standing straight up, which means the 2 triangles are similar. by similarity, (y-x)/y=6/15 15(y-x)=6y 15y-15x=6y 9y=15x y=5/3x differentiate both sides with respect to t or time. dy/dt=5/3dx/dt you know dx/dt=4(ft)/s because ...
A man repays a loan of $3250 by paying $20 in the first ... - Socratic
2016年11月29日 · Define p_k as the payment in the month k+1. We have: p_0=20$ p_k=20$+k* 15$ for k=1,2,... At the end of the n-th month the total payment is: P_(n-1) = 20+ sum_1^(n-1)p_k = 20 + sum_1^(n-1) (20+15k)= 20n +15 sum_1^(n-1) k Using Gauss' formula for the sum of the first (n-1) integers: P_(n-1) = 20n + 15frac (n(n-1))2 express this as an equation in n and pose P_n=3250$ 3250 = 20n + 15frac (n(n-1 ...
In how many ways can four men and four women be seated
2018年4月26日 · 144 If we consider the question for a second, with each man being flanked by 2 women, the seating arrangement must be set up as MWMWMWMW (around a table). Let's put a M in seat 1, then W must be in seats 8 and 2, and so on. This arrangement gives 4!xx4!. We also need to account for the fact that we can start at seat 1 being a W, and putting M in seats 8 and 2, and so on. And so we get 2xx4!xx4 ...
A spotlight on the ground shines on a wall 12 m away. If a man 2 …
2018年3月19日 · dy/dt=0.6 m/s . At the specified moment in the problem, the man is standing at point D with his head at point E. At that moment, his shadow on the wall is y=BC. The two right triangles DeltaABC and DeltaADE are similar triangles. As such, their corresponding sides have equal ratios: (AD)/(AB)=(DE)/(BC) 8/12=2/y, :. y=3 meters If we consider the distance of the man from the building as x then ...
A family has 3 children. Find the probabilities. A) all boys B) All ...
2017年4月19日 · We have 3 children, with each one possibly being a boy or a girl. And so for each child, the probability of being a boy is #1/2# as is the probability of being a girl #1/2#
For s, p, d, and f orbitals, how many electrons can each hold?
2016年8月11日 · See below. The subshells s, p, d, and f contain the following number of orbitals respectively, where every orbital can hold up to two electrons maximum: s: 1 orbital, 2 electrons. p: 3 orbitals, 6 electrons. d: 5 orbitals, 10 electrons. f: 7 orbitals, 14 electrons.
Combinations and Permutations - Statistics - Socratic
At a restaurant, you can choose from 2 appetizers, 4 main courses, and 3 desserts. How many different meals, each consisting of one appetizer, one main course, and one dessert, can be created?
A man flies a kite with a 100 foot string. The angle of elevation of ...
2018年4月24日 · The kite is approximately 78.80 feet off of the ground. If we assume that the string his held taut without any swag, we can use a right triangle to solve for the height of the kite. For this triangle with a reference angle of 52^o, the hypoteneuse is 100ft and the h is the height on the opposite side of the triangle from the reference angle. Sine of an angle is the ratio of the opposite side ...
Supposed that a department contains 10 men and 15 women.
2016年2月27日 · There are 96460 ways to form the committee. First we ask, how many ways are there to choose r objects out of n distinct objects? The answer turns out to be ((n),(r)) = frac{n!}{r!(n-r)!} So for example, how many ways are there to choose 2 men out of 10 men? The answer is ((10),(2)) = frac{10!}{2! * 8!} = 45 Now, with the condition that there must be more women than men, we are left with only 3 ...
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